Directions: Use the digits 1-9 each once to make a the largest possible sum.

### Hint

### Hint

What assumptions are we making about the fractions we are able to use? Do fractions have to be in lowest terms? How can we figure out if we want the larger numbers to be part of the addends or sum?

### Answer

### Answer

Coming soon?

Source: Robert Kaplinsky and Ellen Metzger

This was a pretty tough problem. Had my class stumped. I eventually came up with 5 and 6/3 + 4 and 8/2 = 9 and 7/1. 9 and 7/1 = 16.

Thanks for the problem.

Just realized my mistake after looking over my work. 6/3 is only 2, which would result in a total of 15 not 16. Back to the drawing board.

My students found this:

2 4/8 + 7 1/3 = 9 5/6