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Directions: Create a three digit number using the whole numbers 0-9 no more than one time each. Try to create the number divisible by the greatest (or fewest) number of the following factors: 2, 3, 4, 5, 6, 8, 9 or 10.



What number should the final digit be such that it is divisible by 2, 5 and 10?

What should the three digits add up to so that it is divisible by 3 and 9?

What should the middle digit be so that it is divisible by 4?



Greatest number of factors:  360 and 720 are both divisible by 2,3,4,5,6,8,9 and 10.
Fewest number of factors:  any three digit prime with unique digits would have none of the given numbers as factors. There are more than 20 such numbers (e.g. 103, 347, 521, 849).

Source: Kelly Zinck

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  1. I believe the answer drop down box is wrong as 360 and 740 are divisible by 2, 3, 4, 5, 6, 8, 9, and 10. The six is missing form the drop down menu answer. Thanks for the cool problem.

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