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Pythagorean Theorem

Directions: Using the digits 0 to 9, at most one time each, fill in the boxes to find two pairs of possible lengths for the missing sides.

Hint

Hint

How do we figure out which side length would be easiest to assume?
How do we figure out the length of the remaining side?

Answer

Answer

The longest possible length for the hypotenuse is 10. If it was 11, you would not be able to make a leg long enough with only two digits. It also can’t be 4 or less as it would b

So, the possible side lengths for the triangles are:

a, b, c
4, √84, 10
4, √48, 8
4, √33, 7
4, √20, 6
4, 3, 5

After removing the solutions that duplicate digits, you are left with two options:

a, b, c
4, √84, 10
4, 3, 5

Source: Robert Kaplinsky

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One comment

  1. A solution that is missing from your list: 4, sqrt(65), 9 (because 16 + 65 = 81)

    I also don’t know how 4, 3, 5 could be an answer because assuming that the two adjacent boxes mean that it needs to be a 2-digit number, you would need to use “05” and “09” in the boxes to make it work. That repeats the 0 digit more than once.

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