Directions: What are the maximum and minimum values for c if x^2 + 12x + 32 = (x+a) (x+b) + c?

### Hint

1) Can c be positive? Negative? Zero?

2) Try multiplying the binomials. Do you see any relationship betwee, a,b, and c?

3) Try graphing the function using this: https://www.desmos.com/calculator/4bpceyyd5j

One of the values can be found by splitting a and b equally as (x+6)(x+6) which gives c=-4. This is the minimum value for c.

There is no maximum value because the further apart a and b are in value, the higher the value of c to balance the equation. (Allowing a or b to be negative makes the upper limit infinite. For example a =1,000,000 b = -999,988.
As long as the sum is 12.)

Source: Jedidiah Butler

## Creating Sequences

Directions: Using the digits 0-9, at most one time each, complete the first three terms …

1. Yes, the further apart a and b are in value, the higher the value of c. However the term 12x must be satisfied; this places limitations on c (sure c is a constant but it is still effected by 12x)
11+ 1 = 12 (11) (1) = 11 32-11 = 21
c has a maximum value of 21 if we are only considering whole numbers

If we consider fractional numbers there is still a max for c
–>11.9 + .1 = 12 (11.9) (.1) = 1.19 32- 1.19 = 30.81

–>11.999 + .001 = 12 (11.999) (.001) = .011999 32 – .011999 = 31.988001

as the value of the difference of a and b increases, the value of c gets closer to 32, but can never be greater than or equal to 32.

The range of c is [-4, 32)

2. Allowing a or b to be negative makes the upper limit infinite. For example a =1,000,000 b = -999,988.
As long as the sum is 12.