Directions: Fill in the boxes below using the digits 0 through 9 at most one time each to make the statement true.

### Hint

### Hint

Could one of the numbers in the first space be 1? 5? Why or why not?

Are there any limits on the size of the sum in parentheses?

### Answer

### Answer

Possible answers:

3(6 + 9) = 18 + 27 = 45

6(3 + 9) = 18 + 54 = 72

9(3 + 6) = 27 + 54 = 81

3(6 + 9) = 18 + 27 = 45

6(3 + 9) = 18 + 54 = 72

9(3 + 6) = 27 + 54 = 81

Source: Julie Wright

Julia,

Great task! I like that there are multiple solutions.

Because you showed the solution (a 2-digit number) as two boxes, I would use two boxes for the addends in the middle. Because I need more coffee, I didn’t “understand” that I needed to use ALL the digits 0 – 9 and since the solution was shown with two boxes for a two digit number, I assumed that each box could only hold one digit. Just a suggestion.

Yes, you need to have a box for each digit.

I like this activity, but I agree with Mindy that the single box appears to indicate a single digit. Also, the instructions say to use each digit “at most” one time.

One solution for the single digit per blank option is:

2(3+5)=7+9=16

While I agree this is a correct solution, the terms in the middle space don’t respectively reflect the terms of the bracket expansion. This adds a further confusion to Mindy’s point.

Hi – 2 of my students worked for a while on this and reached total frustration. To help them, I checked the answer, to see if I could offer guidance. It was only then that we realized that the single boxes sometimes represent two digits and sometimes represent one digit!! AAARGH!! And now I see that people have commented on that previously. Should have read the comments. Can you revise this one so that it is consistently 1 box – 1 digit? Thanks! And, yeah, we didn’t get that we needed to use all the digits. Otherwise, awesome!