Directions: Using the digits 0 to 9 at most one time each, fill in the boxes to make the greatest possible product.

### Hint

What digits would make good/bad exponents?

What digits would make good/bad bases?

What digits would make good/bad bases?

### Answer

The greatest product that’s been found so far is 80 = 5^1 * 2^4.

Source: Robert Kaplinsky

Why not 96 = 2^5 x 3^1

I agree…we found that one this week, too!!! 🙂

El dijito seria el mismo porque seria 97=2 5 x 3 1

I agree

we got 81= 9^2 x 7^0

81 multiply by zero is zero

But anything (except 0)to the power of 0 is 1, not 0.

80=5^1*2^4

i did _____________=9^8×7^6

80=5^1×2^4

I 96 because 6^1 × 4^2 is equal to that.

You can only use each digit once. You used the 6 twice.

i did 96=2^5+3^1

this is very hard

Why not 96=2^5+3^1

80= 5^1*2^4

That´s exactly what i thought 96=2^5+3^1

I think it would be 80 = 5^1*2^4

5.0644e12 =

5.0644e12 =

96=2^5 x 3^1

80=5^1 * 2^4

Why is this so hard

You did a terrific job! This post seem extremely great.

I am not very sure but i am guessing that it would be 93= 2^5* 3^2 This is kinda confusing to me so i think i might be a bit off

that gives 32 * 9 = 288 which is not a 2 digit number and uses 8 and 2 twice

I did 9^2*3*2=

I got 96 = 6^1 x 4^2

You used the digit 6 twice.

I did 64=1^0*8^2 because anything to the power of one equals zero.

59= 1^0 × 8^2

50 = 2^1 * 5^2

96 = 2^5 * 3^1

Your first one doesn’t work, because you can only use each digit once, and you used 2 twice.

up i did 8⁹*6⁷ and got 37,572,373,905,408 i think i did something wrong oops

I love that one box represents only one digit. This is also a great exercise in order of operations. Thank you! It was also great that I realized the larger digits had to be the product AND the product had to be less than 100.

4^2 x 5^1 = 16 x 5 = 80

but even larger

2^5 x 3^1 = 32 x 3 = 96

I got 96=2^5*3^1 which is 32×3

2^5*3^1 = 96

we did addition in sted of multiplication so I got 4^3+2^5