Directions: Using the digits 0-9, no more than once, complete the puzzle so that the sum of each side is equivalent.

### Hint

The sum of the middle numbers on opposite sides are always the same

### Answer

There are multiple answers, for example, you can arrange the numbers, 0, 1, 2, 3, 4, 5, 6, 7 in such a way that the sum of each side equals 9. Another solution includes using 0,5,7,3,2,6,4,8 and have sums of 12.

Source: Joshua Nelson and Renee Owen

0,7,3,2,6,5,1,4 and each side equals 9

If each sides equals 9 then it is 0,4,5,3,1,6,2,7

0+4+5=9

5+3+1=9

1+6+2=9

2+7+0=9

I don’t understand yours. 0,7,3,2,6,5,1,4. Can you explain please?

0+7+3=10

3+2+6=11

6+5+1=12

1+4+0=5

0,7,4,6,1,2,8,3 and each side equals 11.

5,4,6,9,0,8,7,3

15

9 2 1

3 6

0 7 5

5, 3, 9 – 9, 1, 7 – 7, 2, 8 – 8, 4, 5 with each side = 17

Has anyone really used this with 1st graders? If so, with an entire class or just a select few?

I’m trying it tomorrow with second graders. We’ve done Ken Ken and I think this will be even more challenging because it is so open ended…

0 ,5,4,3,2,6,1,8,0

I think it is 9

2 5 3 6 1 9 0 8 2 = 10

90354621 equals 12

I did each side equals 17

7+4+6

1 3

9+0+8

Sums = to 9, 10, 11, 12, 13, 14, 15, 16, 17, 18 are all possible

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