Directions: Using the digits 1 to 9 at most once each time, fill the boxes to make the greatest possible product.

### Hint

### Hint

What denominators can you use that will make a one-digit denominator?

### Answer

### Answer

Once answer is 9/4 * 7/3 = 5 2/8.

Source: Marc DeArmond

my problem was 8/5 x 6/4= 2 2/5. I know my numbers repeat and we have to find a way to not repeat a number but i got stuck and couldn’t think of another answer. My strategy was to use the answer given to help and then take one away from 9 making it an 8 and putting it over the 4 and taking one away from the 7 and putting it over the 3 and trying that. My strategy didn’t work. This was a really hard puzzle.

I had 6/2 x 3/1 = 9. I got this by finding a number that times by something would be under ten. I first got 6/2 and that got me 3. Then i got 3 from 3/1. Lastly i multiplied 3 by 3 and got 9. I agree it was a challenging puzzle.

I got 9/4×7/3=5 2/8

I got 9/4 x 7/3 = 5 2/8

I got this 9/4×7/3=5 2/8

I got 9/4times 7/3=5 2/8

For my answer to that question I got 9/4 x 7/3 = 5 2/8. I got that by trying to make a very high number with the digits multiple times. At last I got one that when simplified, not all the way had no repeating digits.

I got 9/4 x 7/3 to equal 5 2/8. I got it by multiplying multiple ways over and over and once I got to 9/4 x 7/3, I realized 9×7= 63, 3×4=12, and 63/12= 5 3/12= 5 1/4= 5 2/8.

9 1/3

i did 9/1 x 8/2= 36

5 2/8

I got 9/4 x 7/3 equals 1 2/8

I got 9/4 * 7/3 = 5 2/8 because this is the highest umber you will get while using numbers 1-9 once.

9/1 x 9/1 = 81/1

I meant : 9/1 x 8/2 = 144/2 = 72

I got 5 1/4

i got 5 2/8

I got 5 1/4 which changed to 5 2/8 to not repeat a number.

didnt mean to right this one

4 1/2 x 2/3= 9/2×2/3=18/3=3

9/4 X 7/3=63/12 =5 3/12

5 2/8

I got 3 1/6 and I had the numbers 2 &7 left over

9 1/3

I did 4/3 x 5/6 which is 7 1/2