Directions: Arrange the digits 1-6 into two 3-digit whole numbers. Make the sum as close to 1000 as possible.

### Hint

Which digits will be the most helpful to focus on to make the solution as close to 1,000 as possible?

### Answer

993 (multiple ways to create the solution)

Source: Ian Kerr

Not able to pick this up in a PDF. Is there a trick to it?

Still not working as a PDF! 🙁

Can’t get it to work either……

Last week when I was online at the site, it allowed me to save to google drive as a pdf. Where did that option go? Please help!

Hi Sondra. I just added it back. It was buggy and I thought no one used it. Glad to be wrong and sorry for the inconvenience.

500+500=1000

dc, you can’t use any zeros.

400+600=1000

devn smith, you can’t use any zeros.

Nico 500+500=1000

Daniel J. Lombardo, you can’t use any zeros.

500+500

1.666+334

2.555+445

Two ways to create 1,000 using no zeros

ashton nguyen, you can’t have any zeros.

900+100=1000

444 + 556 = 1000.

I believe you’re supposed to use *all* the digits 1 – 6 in forming the two numbers. (And, you can only use each digit one time…)

500+500

I’m posting a “general” comment, b/c so many responses/comments are erroneously doing one of the following:

1) Including decimal values (problem states that the two numbers must be *whole* numbers)

2) Including the digit zero (not allowed)

3) Failing to use each of the digits 1 – 6 one time each.

500+500=1000

441+559=1000

IM Jr but my name is really YAEL SANTOS

500+500

700+300

399+501

500+500=1,000

900+100=1000

400+600=1,000

you cant have zeros, Sai.M

666+334=1,000

one hundred plus nine hundred equals one thousand

it is so easy.

The answer given above states that the closest sum to 1000 that you can form from the digits 1 – 6 is 993.

I believe there are 16 different ways to do so, with one example being: 431 + 562.

561 + 432 = 993

So close! It is not possible to get to 1,000.