Open Middle®
Directions: Using the digits 0 to 9, at most one time each, place a digit in each box to make the equation true.
Hint
What are the possible numbers of the coefficient of x?
Therefore what needs to go in the binomial squared?
What would normally be the last number in a perfect square trinomial? Therefore what is the last number here?
Therefore what needs to go in the binomial squared?
What would normally be the last number in a perfect square trinomial? Therefore what is the last number here?
Answer
x^2+10x+28=(x+5)^2+3
x^2+10x+29=(x+5)^2+4
x^2+10x+34=(x+5)^2+9
x^2+12x+43=(x+6)^2+7
x^2+12x+45=(x+6)^2+9
x^2+14x+52=(x+7)^2+3
x^2+14x+58=(x+7)^2+9
x^2+16x+73=(x+8)^2+9
x^2+10x+29=(x+5)^2+4
x^2+10x+34=(x+5)^2+9
x^2+12x+43=(x+6)^2+7
x^2+12x+45=(x+6)^2+9
x^2+14x+52=(x+7)^2+3
x^2+14x+58=(x+7)^2+9
x^2+16x+73=(x+8)^2+9
Source: Kate Nerdypoo