Open Middle®
Directions: Using the integers -9 to 9, at most one time each, place an integer in each box to create three quadratic equations: one with two imaginary solutions, one with one real solution, and one with two real (rational or irrational) solutions.
Hint
How could you use the discriminant to help you identify each of the quadratics?
Answer
There are many possible solutions. One such set of answers could be: two imaginary solutions 0=2x^2 + 0x + 8, one real solution 0=1x^2 + -6x + 9, two real (irrational) solutions 0=5x^2 + 7x + -3.
Source: Ryan D. Fox
1x^2+0x+9=0 x=+ or – 3i
4x^2+3x+-1=0 x=0.25, -1
2x^2+-8x+8=0 x=2
easy peshooteasy with THE POWER OF MINUS EIGHT
thx for prob tho