Directions: Old Mother Hubbard is baking cookies so her cupboards won’t be bare anymore! She bakes 109 cookies in all. She bakes the cookies on 4 cookie sheets. Each cookie sheet is arranged into equal rows and columns, but not every cookie sheet has the same number of rows and columns.

Using digits 0-9, at most once, how might the cookies be arranged on the cookie sheets?

(_ x _) + (_ x _) + (_ x _) + (_ x _) = 109

### Hint

Since you’re only using 8 of the digits 0-9, which might you not use? What are the possible combinations of factors that could be used on each cookie sheet? What are the possible combinations of products that could add to 109? How can you organize your trials to eliminate repeating the same combination?

### Answer

Answer 1: ( 6 x 8)+ (7 x 4) + (3 x 5) + (9 x 2) = 109

Answer 2: (4 x 8) + (7 x 2) + (3 x 6) + (9 x 5 )= 109

** There are probably more correct answers.

Answer 2: (4 x 8) + (7 x 2) + (3 x 6) + (9 x 5 )= 109

** There are probably more correct answers.

Source: Linda Hutcheson

9×8=72

7×3=21

5×2=10

1×6=6

72+21+10+6=109 😀

(4×3)+(7×2)+(3×6)+(9×2)=109

(6×8)+(7×4)+(3×5)+(9×2)=109

(6×8)+(7×4)+(3×5)+(9×2)=109 is what i got

9×5+3×8+4×7+2×6=109

5×5, 5×5, 4×7, 4×7,

Each number used only once, at most.

(7X5)+(6X6)+(8X3)+(2X7)=109

THIS IS MY ANSWER

4×9 5×8 7×3 6×2 is 109.

6X8=48 9X2=18 7X4=28 3X5=15 total is 109

48+18+28+15=109

5×8 + 7×3 + 4×9 x 6×2=109

(7×5)(6×6)(8×3)(2×7)=109

6X8=48 9X2=18 7X4=28 3X5=15 total is 109

48+18+28+15=109

（5*9）+（3*8）+（3*5) + (5*5)=109

45+24+15+25=109

(6 x 8= 52)

(7 x 5= 35)

(5 x 2= 10)

(4 x 3= 12)

52+35+10+12=109

(4 x 8) + (7 x 2) + (3 x 6) + (9 x 5 )= 109

Answer 1: ( 6 x 8)+ (7 x 4) + (3 x 5) + (9 x 2) = 109

Answer 1: ( 6 x 8)+ (7 x 4) + (3 x 5) + (9 x 2) = 109 is this it

(6 x 8)+ (7 x 8)+ (3+5)+ (9 x 2) = 109

(9 x 7) + (8 x 5) + (6 x 1) + (0 x 2) = 109

7×2=14

3×6=18

4×8=32

9×5=45

90+10=100+9=109

(9×8)+(7+5)+(2×1)+(0x6)=109

(4×8)+(7×2)+(3×6)+(9×5)=109