Directions: Using the digits 1 to 9 at most one time each, fill in the boxes to create an equation such that the solution is closest to zero.

### Hint

### Hint

What are some numbers that are close to zero?

What kind of numbers would you put in for the coefficients of x?

What kind of numbers would you put in for the coefficients of x?

### Answer

### Answer

There are many equations that will get to the correct answer of 1/8 or -1/8. Here are some possible equations examples:

9x + 3 = 1x + 4

1x + 7 = 9x + 8

Source: Daniel Luevanos

5x+2=4x+4

I’m not sure you read the directions closely enough. First that solution is fairly far from zero. Additionally, you cannot reuse 4.

9x + 3 = x + 2

Anon is right

you have to do the problem

If this is a question

5x+2=4x+4

_4. _4

X+2=4

_2. _2

X=2

2x+4=x+8

-x -x

_________

1x+4=8

-4 -4

________

1x=4 x=4

1 1

4x+2=5x+3

9x+3=1x + 4

1x+1=3x+2

I’m new to open middle, can you combine digits and use, for example 987x and 1x?

No Scott, only one number per box.

Wouldn’t 1/9 or -1/9 be closer to 0 than 1/8 or -1/8? What about the equation 9x+2=0x+1?

nevermind just re-read that it was 1-9 not 0-9. The desmos version includes the 0.

Yeah, that one is similar but different.

1x+7= 9x+8

9x + 3 = x +2

9x + 3 = x + 2

9x+8=1x+7

7x – 4 = 3x – 6

Can we have a different equation from the problem across the equal sign ?

8x + 4 = 5 – 2x

8x+4=5-2x

1x+1=1x+1

You can only use each number once, you used 1 four times. Also, zero is not the only solution to yours.

2x + 8= 1x + 8 is exactly 0

-1x -1x

x + 8 = 8

-8 -8

x=0

You can only use each number once

9x+3=1x+4

1x+7=9x+8

6x+4=1x+9

1x+7= 9x+8

7x+4=5x+7

4x+6=2x+8