Directions: Using the digits 0 to 9 at most one time each, fill in the boxes to create a three-digit number. Try to create a three-digit number divisible by the greatest (or fewest) amount of the following factors: 2, 3, 4, 5, 6, 8, 9 or 10.

### Hint

What number should the final digit be such that it is divisible by 2, 5 and 10?

What should the three digits add up to so that it is divisible by 3 and 9?

What should the middle digit be so that it is divisible by 4?

### Answer

Greatest number of factors: 360 and 720 are both divisible by 2,3,4,5,6,8,9 and 10.

Fewest number of factors: any three digit prime with unique digits would have none of the given numbers as factors. There are more than 20 such numbers (e.g. 103, 347, 521, 849).

Fewest number of factors: any three digit prime with unique digits would have none of the given numbers as factors. There are more than 20 such numbers (e.g. 103, 347, 521, 849).

Source: Kelly Zinck

I believe the answer drop down box is wrong as 360 and 740 are divisible by 2, 3, 4, 5, 6, 8, 9, and 10. The six is missing form the drop down menu answer. Thanks for the cool problem.

Thank you for that catch Brad! The correction has been made.

740 is NOT divisible by 3…or 6…or 8…or 9!!

Problem states 720 not 740.

you should put 180 in “2, 3, 4, 5, 6, 8, 9”

720

810

360- can be divided by 2, 3,4,6, 9and 10

360 has the greatest

The number 360 is divisible by them all.

720

divisible by all

360 is the least number divisible by all.

720

720

Always a good day to learn something new! 😉

Who else did this at an AVID conference? Sacramento June 20222.

360 and 720

Mat