Directions: Using the digits 1 to 9, at most one time each, fill in the boxes to make the following expression as close to 0 as possible.

### Hint

### Hint

What are all the perfect square three digit numbers? Several of these can’t be used since they contain a repeated digit (e.g. 121 uses the digit 1 twice and 144 uses the digit 4 twice)

### Answer

### Answer

Using Perfect squares:

Sqrt(256) – sqrt(81) – sqrt(9) = 4

Sqrt(256) – sqrt(81) – sqrt(9) = 4

Using non-perfect squares:

Sqrt(145) – sqrt(92) – sqrt(6) = 0.00044178938368

Source: Erick Lee

Dang it.

I got:

√124 – √89 – √3 = -0.030503214

You tried. That is what is important!

Good job!! It doesn’t matter if you make a mistake! The important thing is that you tried! You did your personal best and that is what matters!!! Just keep trying and you will make a good answer eventually!! Just do your personal best and if you get it wrong than don’t worry about it! it is fine! Keep on trying!

Should it not be √256 – √81 -√49 = 0 ?

Your answer looks correct. Maybe the wording needs to be clarified? It says as close to zero, maybe the question needs to state without equaling zero?

The last term has space for only one digit, so √49 doesn’t work.

I thought there could only be one digit square root on the last term?

Correct Kathy and Suzanne. Unfortunately Kristen, the last root must have a single digit.

256-81-9=4

The answer should be

√121-√81-√4

The answer to this equation would be 0

or 11-9-2 when It is simplified

or √121-√64-√9

The answer would be 0 as well

you are repeating the number 1 , 121 has two and then theres a third “1” in 81

/121-/64-/9=0

257-81-49=4

|256|-|81|-/9/=4

|121|-|81|-|4|

|121|-|81|-|5|

|121|-|82|-|5|

121-81-9= 4