...Note if you remove the restriction of having a “single digit in both the numerator and denominator” there are other answers as Tim Clifford comments below. Source: Dr. Brian Lack...
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Adding Decimals (Middle School)
...box represent? Answer No answers yet. If you have one, post it in the comments. Note: This problem’s difficulty can be adjusted by altering the number of digits (boxes), picking...
Read More »Subtracting Decimals (Middle School)
...box represent? Answer No answers yet. If you have one, post it in the comments. Note: This problem’s difficulty can be adjusted by altering the number of digits (boxes), picking...
Read More »Multiplying Decimals (Middle School)
...the largest product with positive factors. We are still looking for answers. If you have one, post it in the comments. Note: This problem’s difficulty can be adjusted by altering...
Read More »Dividing Decimals (Middle School)
...box represent? Answer No answers yet. If you have one, post it in the comments. Note: This problem’s difficulty can be adjusted by altering the number of digits (boxes), picking...
Read More »Product of Distributive Property
Directions: Decide if 30x – 12 could be a result of using the distributive property. If it is, find the possible combinations of factors whose product would be 30x –...
Read More »Parallel Lines and Slope
...What does it mean for lines to be parallel? How can you compare pairs of points so that the lines going through the pairs of points are parallel? Answer Here...
Read More »Perpendicular Lines and Slope
...What does it mean for lines to be perpendicular? How can you compare pairs of points so that the lines going through the pairs of points are perpendicular? Answer Here...
Read More »Adding Decimals to Make Them As Close to One as Possible
...with students, I would suggest putting the decimals side by side. Also, the idea behind absolute value may come up during the lesson. Specifically, is 0.997 (a difference of -0.003)...
Read More »Properties of Integer Exponents
...powers? Answer There are many possible solution combinations. The power pairs would be & 9, 1 & 8, 2 & 7, 3 & 6, 4 & 5 Source: Bryan Anderson...
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