Tag Archives: DOK 2: Skill / Concept

Sector Area 1

Directions: Using the digits 0 to 9 at most one time each, place a digit in each box so that the radius and angle measure result in the sector area. Source: Robert Kaplinsky

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Geometric Proofs

Directions: Using exactly five geometric markings to show that a quadrilateral is a square. Source: Robert Kaplinsky

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Area on a Coordinate Plane 1

Directions: Using the integers -9 to 9 at most one time each, fill in the boxes to create coordinates that represent the vertices of two triangles: one with an area of less than 55 units2 and one with an area of more than 55 units2. You may reuse all the integers each time. Source: Robert Kaplinsky

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Perpendicular Lines 1

Directions: Using the digits 0 to 9 at most one time each, fill in the boxes to create two perpendicular lines. Source: Robert Kaplinsky

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Equation of a Circle 1

Directions: Using the digits 1 to 9 at most two times each, place a digit in each box to make two circles: one with an area of less than 10 units2 and one with more than 10 units2. Source: Robert Kaplinsky

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Properties of Exponents 3

Directions: Using the digits 1 to 9 at most one time each, fill in the boxes twice to make an equation. You may reuse all the digits for each equation. Source: Robert Kaplinsky

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Systems of Inequalities 1

Directions: Using the integers −9 to 9 at most one time each, place an integer in each box to create a system of inequalities as well as an included and excluded point. Source: Robert Kaplinsky

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Systems of Equations 3

Directions: Using the integers −9 to 9 at most one time each, place an integer in each box to create a system of equations and its solution. Source: Robert Kaplinsky

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Arithmetic Sequences 1

Directions: Using the integers −9 to 9 at most one time each, place an integer in each box to create an arithmetic sequence and a function that represents it. Source: Robert Kaplinsky

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Systems of Equations 1

Directions: Using the integers -9 to 9 at most one time each, fill in the boxes to create a system of equations with a solution in Quadrant 2. Source: Robert Kaplinsky

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